WebJan 6, 2024 · No matter what the value of k is, we can take y = 0 to satisfy the equation. Substituting into the first equation, we find x = − 3. Now we can check that x = − 3, y = 0 … WebMay 23, 2016 · Since it is given that you have to find suitable k for the problem to have unique solution asserts that problem has already unique solution. i.e. rank of matrix = rank of augmented matrix = no. of unknowns=3. i.e. rank of matrix should be 3.means determinant should be non zero.rank of augmented matrix should be 3 as well and rank of …
For what value of k does the following system have a unique …
WebSep 14, 2014 · This determinant can be worked out by hand resulting in the equation. 2k - 8 + 55 -40 +22 - k = 0. The solution is k = -29. With k = -29 there are two possibilities. There could be no solution or an infinite number of solutions. If the latter (which we would like to rule out), there will be a solution for which z = 0. WebASK AN EXPERT. Engineering Electrical Engineering Problem (6) Consider the control system shown in Fig. 6. Determine the value of K and T of the controller G. (S) such … dgsa online training
How to find the critical gain K from the root locus
WebDetermine values of K for which the system is consist. Transcribed Image Text: 9x,+ K Xz =9 K XI + Xz= -3 Branch of mathematics concerned with mathematical structures that are closed under operations like addition and scalar multiplication. It is the study of linear combinations, vector spaces, lines and planes, and some mappings that are used ... WebApplying the Routh-Hurwitz criterion, the closed loop system is stable if K > 32 (from the s0 row) and K > −200/6 (from the s1 row), so we need K > 32. (b) Now select a value of K that produces the least overshoot and plot the step response of the closed-loop system. Be sure to use a time range that shows the important aspects of the behavior. WebOct 26, 2024 · Now I'm trying to determine the value of K so that I have a marginally stable system. I'm not supposed to use the Routh-Hurwitz method. I'm thinking hard but I seem to get to nowhere. I know that for the system to be marginally stable I will need a real pole in the left complex plane and two complex conjugate pure imaginary poles. cicero and horace translation