WebCan you solve this real interview question? Largest Number - Given a list of non-negative integers nums, arrange them such that they form the largest number and return it. Since the result may be very large, so you need to return a string instead of an integer. Example 1: Input: nums = [10,2] Output: "210" Example 2: Input: nums = [3,30,34,5,9] Output: … WebJul 2, 2024 · This example shows you how to find the second largest number in an array of java. Step 1: Iterate the given array. Step 2 (first if condition arr[i] > largest): If current array value is greater than largest value then. Move the largest value to secondLargest and make. current value as largest. Step 3 (second if condition arr[i] > secondLargest )
Codeforces Round #842 (Div. 2) Editorial - Codeforces
WebStep 1- Declare a function for finding the second largest number Step 2- Use sort () method to sort the list Step 3- Return the second last element in the list after sorting using negative indexing Step 4- Declare a list and take input or initialise values Step 5- Call the function Step 6- Print the value returned by the function Python Program 1 WebAnswer. The formula to calculate total number of bytes required by a two-dimensional array is as follows: total bytes = number-of-rows x number-of-columns x size-of-base-type. = 5 x 24 x 2 (since short requires 2 bytes in memory) = 240 bytes. Answered By. 3 Likes. bunbury street art
Program to find largest and second largest number in array
WebFind 2nd Largest Number in Array using Arrays. Let's see another example to get second largest element or number in java array using collections. import java.util.Arrays; public … WebNov 4, 2024 · Use the following algorithm to write a program to find second largest number in an array; as follows: Start Program. Take input size and elements in array … WebIn the picture above, 12 is the largest number in the array, and was compared to 3, 1, 11, and 10 in the first pass. In the second pass, we find the largest among {3, 1, 11, 10}, which is 11, which is the second largest number in the original array. Time Complexity: All elements must be looked at, therefore, n - 1 comparisons for pass 1. bunbury street names